z^2-7z+(13-i)=0

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Solution for z^2-7z+(13-i)=0 equation:


Simplifying
z2 + -7z + (13 + -1i) = 0

Remove parenthesis around (13 + -1i)
z2 + -7z + 13 + -1i = 0

Reorder the terms:
13 + -1i + -7z + z2 = 0

Solving
13 + -1i + -7z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -1i + -7z + -13 + z2 = 0 + -13

Reorder the terms:
13 + -13 + -1i + -7z + z2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -1i + -7z + z2 = 0 + -13
-1i + -7z + z2 = 0 + -13

Combine like terms: 0 + -13 = -13
-1i + -7z + z2 = -13

Add '7z' to each side of the equation.
-1i + -7z + 7z + z2 = -13 + 7z

Combine like terms: -7z + 7z = 0
-1i + 0 + z2 = -13 + 7z
-1i + z2 = -13 + 7z

Add '-1z2' to each side of the equation.
-1i + z2 + -1z2 = -13 + 7z + -1z2

Combine like terms: z2 + -1z2 = 0
-1i + 0 = -13 + 7z + -1z2
-1i = -13 + 7z + -1z2

Divide each side by '-1'.
i = 13 + -7z + z2

Simplifying
i = 13 + -7z + z2

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